Hi, Everyone.
Same issue here, for me I always fail validators 4 and 6, it’s probably something very stupid , but i can’t find it.
I check if the N number is < 50 , i check if message in a regexp are in [A-Z],. I don’t really understand what some mean by the original size message , i should only write the 50 first chars ?
Hi, if someone else has this issue, just use a custom test case with a very long message.
just beware of borders (values < or > to the 26 chars when converting)
beware to negatives values
beware to end of lines (fgets default on some tests)
can you please eleborate? I cant decode it even manually.
To be simple for the encoding with the word "ABCD" :
Step 1: apply CAESAR with the incrementing number (let’s say 4 here)
"A" + (4+0) = "E"
"B" + (4+1) = "G"
"C" + (4+2) = "I"
"D" + (4+3) = "K"
"ABCD" becomes "EGIK"
Step 2 : translate trough first rotor (let’s say "BDFHJLCPRTXVZNYEIWGAKMUSQO" here)
FROM | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
↓ ↓ ↓ ↓
TO | B D F H J L C P R T X V Z N Y E I W G A K M U S Q O
"EGIK" becomes "JCRX"
Step 3 : translate trough second rotor (let’s say "AJDKSIRUXBLHWTMCQGZNPYFVOE" here)
FROM | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
↓ ↓ ↓ ↓
TO | A J D K S I R U X B L H W T M C Q G Z N P Y F V O E
"JCRX" becomes "BDGV"
Step 4 : translate trough third rotor (let’s say "EKMFLGDQVZNTOWYHXUSPAIBRCJ" here)
FROM | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
↓ ↓ ↓ ↓
TO | E K M F L G D Q V Z N T O W Y H X U S P A I B R C J
"BDGV" becomes"KFDI"
So after those 4 steps "ABCD" is encrypted to "KFDI"
To do decryption of “KFDI” :
Step 1 : translate from third rotor (let’s say "EKMFLGDQVZNTOWYHXUSPAIBRCJ" here)
FROM | E K M F L G D Q V Z N T O W Y H X U S P A I B R C J
↓ ↓ ↓ ↓
TO | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
"KFDI" becomes"BDGV"
Step 2 : translate from second rotor (let’s say "AJDKSIRUXBLHWTMCQGZNPYFVOE" here)
FROM | A J D K S I R U X B L H W T M C Q G Z N P Y F V O E
↓ ↓ ↓ ↓
TO | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
"BDGV" becomes "JCRX"
Step 3 : translate from first rotor (let’s say "BDFHJLCPRTXVZNYEIWGAKMUSQO" here)
FROM | B D F H J L C P R T X V Z N Y E I W G A K M U S Q O
↓ ↓ ↓ ↓
TO | A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
"JCRX" becomes "EGIK"
Step 4: undo CAESAR with the incrementing number (let’s say 4 here)
"E" - (4+0) = "A"
"G" - (4+1) = "B"
"I" - (4+2) = "C"
"K" - (4+3) = "D"
"EGIK" becomes "ABCD"
So after those 4 steps "KFDI" is decrypted to "ABCD"
11 Likes
Thank you very much 
Same sh*t, could I get test cases for 4, 6 tests?
Considering the number of people facing an issue with this puzzle (+ lots of these issues seem to come from the fact that tests are shorter than validators, in particular <26 the size of the alphabet), I added two hopefully helpful testcases.
2 Likes
Thank you, this explanation of is a lot clearer than the one included in the exercise.
Hi,
I passed all the tests for the Enigma Encryption/Decryption, but once submitted validators 1 and 2 fails.
I don’t understand why !
What are differences between validator test and ide test ?
In my code i have no hard-coded values, all contraints are implemented.
Can i have the test game of validator 1 and 2 to fixe my issue ?
Hi Sudeep,
All the test cases work but when I click on submit, I only have 66%. The test cases 4 and 5 do not work and I frankly have no idea why.
My test case for the decoding is the following :
(((int)message4.charAt(i))-pseudoRandomNumber-i-65)%26+65<65
1 Like
Thank you very much, was very helpful! 
Hi,
Same for me here, I’d like to be able to see validators 1 and 2 to understand what I’m doing the wrong way!
Thanks,
Hello,
There is a problem with the starter code (aka auto generated code) for C, it does not read in the input properly.
The line:
fgets(rotor, 27, stdin);
it should be
fgets(rotor, 27, stdin); fgetc(stdin);
Can this be corrected?
@The_Auditor Ok so you posted this issue at 3 places at the same time. It’s fixed (and I’ve answered somewhere else).
@Niako thanks for correction. Sorry for multiple posts, was not sure which of the 3 locations was the right one. Will be more patient in the future.
Hey!
I have a problem, I can’t pass the validator n°3
I don’t exactly understand why as some of you seems to have problems on validators 4 and 6, I guess it’s a special exception in the validator 3 that’s not in every other codes.
Could someone help me in DM or on Discord ? Thanks in advance !
(PS : My Discord is Thomas “Sigeth” S.#9015 if you want to DM me, I’m on the official CodinGame server)
I’ll share it here, it’s simpler for everyone:
Validator 3:
Input:
DECODE
8
BDFHJLCPRTXVZNYEIWGAKMUSQO
UXBLHWTMCQGZNPYFVOEAJDKSIR
EKMFLGNTOWYHXUSPAIBRCJDQVZ
EPXAMAGWGUWQSTPTYPOCMYYJPGUEWCVGGCEZKANOQ
Output:
BETTERTHREEHOURSTOOSOONTHANAMINUTETOOLATE
Good luck!
1 Like
Ok I understood why.
To describe my problem, I understood the statement “If the second ROTOR is AJDKSIRUXBLHWTMCQGZNPYFVOE” as a condition that we needed to check out in our code.
Well, thanks for giving me the validator !
Hello,
Just have passed all test but im having 66% at the end, whats the problem?
im using C++.
Thanks in advance.