[Community Puzzle] Hill Notation and Hill Order

Puzzles
#1

https://www.codingame.com/training/hard/hill-notation-and-hill-order

Send your feedback or ask for help here!

#2

Hey there,

Quick question about ‘Hill Notation’ community puzzle:
Validators ‘Quantity Sort’ and ‘Bigger Sort’ fail on submit, but pass their test cases.

Anyone got some compounds to play around with? (I am not a chemist ;))

P.S.: It would be great if we could have dedicated forum sections for each community puzzle as soon it gets approved, thoughts?

1 Like
#3

Maybe your sorting machine is wrong?

#4

Pretty sure about that :wink:

#5

Remember that you have to sort inside a component and the components themselves.

#6

Try these tests:

1

2
C11H13NO
CCl4

Answer:

CCl4
C11H13NO

2

2
CH3CO2H
C2H4

Answer:

C2H4
C2H4O2

3

2
HCONH2
CH2F2O

Answer:

CH2F2O
CH3NO

4

2
C11H13NO
C2H4NO2

Answer:

C2H4NO2
C11H13NO

These exercise some of the relationships that I struggled a bit with on this puzzle. Hopefully you will gain some insight.

  • danBhentschel
2 Likes
#7

Thanks, that will help!

#8

Hi, I have the same problem. I past all test but fail in submit in validators ‘Quantity Sort’ and ‘Bigger Sort’.

I’ve tried examples of player_one and I pass that examples too.

Can anyone try this test?

3
C12H11O2
C12H11O3P5
C12H11O1P6

In my interpretation, (and apparently in original Hill text) C12H11O1P6 < C12H11O2 < C12H11O3P5 because first is alphabetically and if two compound have same atom, look for quantity.

I think the problem is in the line of puzzle: " If the elements are in the same order, the one with fewer of the element is sorted first." So, maybe the correct is: C12H11O2 < C12H11O1P6 < C12H11O3P5 because only look the quantity if there is exactly the same atoms names.

So, Can anyone test those compounds for me? and Can anyone provide some more tests?

Thanks

#9

My output for this is:

C12H11OP6
C12H11O2
C12H11O3P5
  • danBhentschel
#10

I don’t understand why is in IDE test case 02:
CCl4 < CHCl3

According to puzzle description:

Hill Order sorts elements in Hill Notation according to the following rules:

  • Compounds are sorted alphabetically by element. So Al2O3 comes before CH4.
  • If the elements are in the same order, the one with fewer of the element is sorted first.

3 < 4, so Cl3 < Cl4, so CCl3 < CCl4, so CCl3H < CCl4
H comes before Cl only in Hill Notation, but according to description Hill Order is fully alphabetical, as in the given example Al2O3 < CH4.

Why is the expected solution is CCl4 < CHCl3 and not CCl4 > CHCl3 ???

EDIT: now I get it. so the Hill Order is not alphabetical, but goes according to Hill Notation order. The given example Al2O3 < CH4 is just misleading. Could have been a nice puzzle. Such disambiguity in the description rendered it as a 1-star puzzle in my book… :frowning: