Coding Games and Programming Challenges to Code Better

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Created by @Edjy,validated by @AlienOGman,@jordan_codingame and @FredericLocquet.

If you have any issues, feel free to ping them.

Coding Games and Programming Challenges to Code Better

Send your feedback or ask for help here!

Created by @Edjy,validated by @AlienOGman,@jordan_codingame and @FredericLocquet.

If you have any issues, feel free to ping them.

The statement is fuzzy, imprecise or incomplete.

I have to deduce the requirement from test cases. Reading the statement alone did not help.

3 Likes

Being a buzzle might be recursive.

1 Like

Thanks for the clue !

+1

I totally agree !

I think that the difficulty level for this puzzle should be set to Medium.

Levels 1-3 are easy, but Buzzle level 4 is quite a bit harder.

3 Likes

How come in the example in level 4, 82 is not a buzzle?

in base 12, k = 7,11; 82 â†’ 6A â†’ sum (6+10), next iteration 16 last digit 6 != 11 && 6 != 7 but the sum is (1+6) = 7 which should be buzzle; or am I misunderstanding the procedure?

1 Like

16 in base 12 is 14 (1x12 + 4x1) and the sum is 1+4=5. Hence itâ€™s not a buzzle

1 Like

Thank you, was not understanding you had to keep on converting to base b the sum; I feel that there should be a distinguish on easy(this) and very easy puzzles

This puzzle is really anoying with the base conversionsâ€¦

Iâ€™m aligned with your statement for all the test case appart test 4 and test 5 where 1039 4518 4564 and 4582 are seen as buzzle on my side if the sum is checked after base conversion.

In the end I donâ€™t find any way to make an algorithm which would be ok with these anthgonious situationsâ€¦ if anyone have an idea on this issue I can share my code.

Make sure your conversion is correct.

For example with 1039 in base 18: 1039 = 3*18Â˛ + 3*18 + 13, therefore sum of the digits is 3+3+13 = 19 which is not a buzzle (not a multiple of 11 or 17). 19 = 1*18 + 1 so the sum of its digits is 2 which is not a buzzle either.
For example with 4518 in base 24 : 4518 = 7*24Â˛ + 20

If you still canâ€™t find the error, please share the code dealing with base conversion