Coding Games and Programming Challenges to Code Better
Send your feedback or ask for help here!
Created by @TheMagicShop,validated by @timbersson,@Lisa-Has-Ideas and @UncleV.
If you have any issues, feel free to ping them.
Coding Games and Programming Challenges to Code Better
Send your feedback or ask for help here!
Created by @TheMagicShop,validated by @timbersson,@Lisa-Has-Ideas and @UncleV.
If you have any issues, feel free to ping them.
Hello,
I pass all the tests, but I fail at validator 4.
As the tests do not contain a sample with empty brackets (), I checked my solution works in this case.
Please, do you have any other idea for check I should do to pass validator 4 ?
Only test case with empty parenthesis, try this: (test())
Edit: I am blind, you literally said you tested it already…
Only test case with unclosed ", perhaps you check them? : (test ’ " ())
Hello, I double-checked validator 4. It is a lisp expression. It is correct from a parenthesis point of view, very similar to example 4, but - fun fact - there is a syntax error: a double-quote that is never closed. Could this make your program fail? Try to make a custom test by copying test 4 but removing the double-quote after “factorial” and see if you program work.
Actually you should ignore any character that is not a parathesis…
I have the same issue (at least I think I have the same issue): the validator 4 is the only one that fail. I have the following outputs for the 2 examples you suggest:
(test ’ " ())
^ ^^^
| |||
| 22|
1-----------1
(defun fact (n) "factorial (if (<= n 1) 1 (* n (fact (- n 1)))))
^ ^ ^ ^ ^ ^ ^ ^ ^ ^^^^^
| | | | | | | | | |||||
| 2-2 | 3------3 | | 5-----5||||
| | | 4------------4|||
| | 3------------------3||
| 2----------------------------------2|
1--------------------------------------------------------------1
I feel like the answer are correct. What did I miss?
Seems correct to me.
An other idea would be: only test case starting with a space:
(fun ( " ()))
Or only text case with a closing parenthesis directly followed by an opening parenthesis. Try: (a+b)(c+(d+c))
I tried both. and others. here are the results (looks fine for me):
(fun ( " ()))
^ ^ ^^^^
| | ||||
| | 33||
| 2-----2|
1-----------1
(a+b)(c+(d+c))((c+d)+c)(a+b)(a+b) (a+b)
^ ^^ ^ ^^^^ ^ ^^ ^^ ^ ^ ^
| || | |||| | || || | | |
1---1| 2---2||2---2 |1---11---1 1---1
1-------11-------1
What did I miss?
I am sorry we could not find the issue.
Try this one:
(a b (c &d (e '())) "f (g (h i) j (k (l m) (n (o p) q))))
(a b (c &d (e '())) "f (g (h i) j (k (l m) (n (o p) q))))
^ ^ ^ ^^^^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^^^^
| | | |||| | | | | | | | | | ||||
| | | 44|| | 3---3 | 4---4 | 5---5 ||||
| | 3-----3| | | 4---------4|||
| 2------------2 | 3-------------------3||
| 2-------------------------------2|
| |
| |
1-------------------------------------------------------1
It also seems good for me
Nop. The outer 1 is one character too long (or too high if you prefer).
This is the expected output:
(a b (c &d (e '())) "f (g (h i) j (k (l m) (n (o p) q))))
^ ^ ^ ^^^^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^^^^
| | | |||| | | | | | | | | | ||||
| | | 44|| | 3---3 | 4---4 | 5---5 ||||
| | 3-----3| | | 4---------4|||
| 2------------2 | 3-------------------3||
| 2-------------------------------2|
1-------------------------------------------------------1
Nice catch! I didn’t saw it. thanks
I am curious to know why this bug did not appear on the examples. Can you explain?